題目:
https://leetcode.com/problems/two-sum/
Given an array of integers, return indices of the two numbers such that they add up to a specific target.
You may assume that each input would have exactly one solution, and you may not use the same element twice.
Example:
Given nums = [2, 7, 11, 15], target = 9, Because nums[0] + nums[1] = 2 + 7 = 9, return [0, 1].
My code:
class Solution(object):
def twoSum(self, nums, target):
"""
:type nums: List[int]
:type target: int
:rtype: List[int]
"""
i=0
while len(nums)>1:
a=nums.pop(0)
if target-a in nums:
return (i, i+nums.index(target-a)+1)
i=i+1
想說只用一個while loop應該還算快,結果還是花了664ms, 只贏了40.95%的人。 前面幾名不用100ms那是怎麼寫的!!??
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張貼留言
Thanks for your message.